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Re: Where.. Then Loop IDL help [message #93772 is a reply to message #93771]

Thu, 13 October 2016 22:08

smnadoum
Messages: 24
Registered: June 2016

Junior Member

On Thursday, October 13, 2016 at 9:39:33 PM UTC-7, Cheryl wrote:
> Hi,
>
> I am new to IDL world, and was wondering if you can help me create a loop.
>
> I need to create an array by replacing all values in 'a' that are greater than 5 by 20.
>
> c= where(a gt 5) then [c] = 20
>
> Is this the correct way to do it?
>
> Thanks

I think i found a way to do it

a[where(a gt 5,/null)]=20 is it correct?? How can I create an array for this?
I tried to do :c= a[where(a gt 5,/null)]=20, but I keep getting a syntax error

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[Message index]

		Where.. Then Loop IDL help By: smnadoum on Thu, 13 October 2016 21:39
		Re: Where.. Then Loop IDL help By: smnadoum on Thu, 13 October 2016 22:08
		Re: Where.. Then Loop IDL help By: Markus Schmassmann on Fri, 14 October 2016 02:25
		Re: Where.. Then Loop IDL help By: smnadoum on Fri, 14 October 2016 11:20

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