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Re: Removing specific elements in an array [message #94533 is a reply to message #94532]

Tue, 27 June 2017 14:57

gombgg
Messages: 7
Registered: November 2013

Junior Member

Mike beat me to it. My response is equivalent:

You shouldn't need loops.

You didn't define what you want to do with the first element, which has no predecessor. You also didn't specify whether your output array is allowed to have neighbouring elements that differ by one. (eg, what should happen if x=[5,10,11,11,11,20] ?)

So long as the last element isn't one less than the first element, this will work:

result=x[where((x-shift(x,1)) ne 1,/null)]

If you want to make sure the last element doesn't mess things up, this should work:

inds=where((x-shift(x,1)) ne 1,count)
if count eq 0 then result=x[0] else begin
if inds[0] ne 0 then inds=[0,inds] ;make sure the first element is included
result=x[inds]
endelse

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[Message index]

		Removing specific elements in an array By: thtran296 on Tue, 27 June 2017 13:17
		Re: Removing specific elements in an array By: Michael Galloy on Tue, 27 June 2017 14:32
		Re: Removing specific elements in an array By: gombgg on Tue, 27 June 2017 14:57

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