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Re: Fill Missing values with NaN [message #94667 is a reply to message #94666] Thu, 10 August 2017 12:03 Go to previous messageGo to previous message
idlusr is currently offline  idlusr
Messages: 2
Registered: August 2017
Junior Member
On Thursday, August 10, 2017 at 12:00:41 PM UTC-7, idlusr wrote:
> How can one do the following in IDL:
>
> time = [1, 4, 7, 8]
> dens =[80,60,30,50]
>
> alltimes = [0,1,2,3,4,5,6,7,8,9]
> densnew = [NaN, 80, NaN, NaN, 60, NaN, NaN, 30, 50, NaN]
>
> i.e., compare time to all times, allowing densnew to have same # of elements as all times but ONLY the densities in dens. Missing elements in densnew (depending on time) are given NaN value.
>
> Thank you!

Forgot to mention, the values in my data set are type double for time & float for density. Thanks again!
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