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do loop [message #93046]

Fri, 15 April 2016 06:13

Ali Gamal
Messages: 98
Registered: June 2013

Member

hi, I have
col1 =dep[0, 0: 49]
col11 =dep[0, 50: 99]
col21 =dep[0, 100:149]
col31 =dep[0, 150:199]
col41 =dep[0, 200:249]
col51 =dep[0, 250:299]
col61 =dep[0, 300:349]
col71 =dep[0, 350:399]
col81 =dep[0, 400:449]
col91 =dep[0, 450:499]
;;;;;;;;;;;;;;;;;;;;;;;;;;
I want to make this as do loop how can i do it ?

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Re: do loop [message #93047 is a reply to message #93046]

Fri, 15 April 2016 07:01

greg.addr
Messages: 160
Registered: May 2007

Senior Member

Don't try to put the indices in the variable name - you'll regret it. Do this instead:

col=reform(dep[0,0:499],50,10)

then you can access your 'col1' with col[*,0], 'col11' with col[*,1] etc.

Otherwise your next question will be "How do I loop through col1, col11...?"

See previous post... https://groups.google.com/forum/?hl=en#!topic/comp.lang.idl- pvwave/XNn-lBi9DGQ

cheers,
greg

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Re: do loop [message #93075 is a reply to message #93047]

Thu, 21 April 2016 08:48

tonyhey
Messages: 1
Registered: April 2016

Junior Member

If you really need the index names, use (ordered) hash variable:
You can use it as normal variables and also loop thru this

IDL>dep = findgen(1,500)
IDL>col = orderedhash()

IDL>for i=0, 9 do $
IDL> col[string(i,form='(i1.1)')+'1'] = dep[0,(i*50):((i+1)*50)-1]

IDL> foreach values, col, name do print,name
IDL> help,col['31']
IDL> print,col['51']

A.

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