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long to float [message #24623]

Thu, 05 April 2001 07:54

Dominik[1]
Messages: 46
Registered: April 2001

Member

Hello,

I have a small problem (i hope)

I read a number (is = -536852787) out of a file. But this number is not a
long, it shoul be a float. It should be sb =6588.00. I am not sure if the
first Number is a big endian, but the second is in little endian.
so, after I multiply the start number with -1 and make byteorder, the same
hexadecimal number is in the memory. It is FF1F33B9, but he shows
e -14732359
Is there a good way to see the stuff in memory as a float and not as a
long??

thanks for helping
Dominik

Example code
pro test

f = -536852787
help, f
print, Format='(Z)', f
f = -1 * f
help, f
print, Format='(Z)', f
byteorder, f
help, f
print, Format='(Z)', f
end

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long to float

By: Dominik[1] on Thu, 05 April 2001 07:54

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