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Re: Inverse Hyberbolic Tangent [message #33346]

Wed, 18 December 2002 10:29

Patrick L. Nolan
Messages: 1
Registered: December 2002

Junior Member

p.pall <p.pall@atm.ox.ac.uk> wrote:

> Does anyone out there know how to compute INVERSE hypebolic tangent in IDL
> 5.5?

> An 'Atanh' function does not appear to exist.

> Does this mean I'll have to mess about with series expansions?

This one is easy to do on paper.
If y = atan(x),
then x = .5 * ln( (1+y) / (1-y) )

Of course you need to worry about singular behavior at
the boundaries and the possibility of invalid y values.

--
* Patrick L. Nolan *
* W. W. Hansen Experimental Physics Laboratory (HEPL) *
* Stanford University *

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		Re: Inverse Hyberbolic Tangent By: Patrick L. Nolan on Wed, 18 December 2002 10:29
		Re: Inverse Hyberbolic Tangent By: notspecified on Wed, 18 December 2002 05:39

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