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Inverting indices? [message #2353]

Wed, 29 June 1994 09:23

kkobayas
Messages: 7
Registered: June 1994

Junior Member

Hi,

I guess I didn't say it right in the subject, but what I want to do
is, say, for i=[1,3,5] as indeces for a 10-element array, I need to find
the indeces for points NOT set by i, that is, j=[0,2,4,6,7,8,9].

Am I making sense? I just need to do j=OPPOSITE(i,10) so that when
i=[1,3,5] it'll return j=[0,2,4,6,7,8,9].

I couldn't find a built-in routine that does this. I tried the following
code:

FUNCTION opposite,idx,n
k = bytarr(n)
k(idx)=1
return,where(not k)
end

but this didn't seem to work for some reason. The shortest working
routine I could come up with is:

FUNCTION opposite,index,n
k = bytarr(n)
k(*)=1
k(index)=0
return,where(k)
end

I somehow feel there must be a more efficient way of doing this. Can
anyone suggest a better solution? Also, why doesn't the first routine work?

--
------------------------------------------------------------ -----------------
| "Would you tell me, please, which way I
Ken Kobayashi | ought to go from here?"
| "That depends a good deal on where you
kkobayas@husc.harvard.edu | want to get to." - Lewis Carroll

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[Message index]

		Inverting indices? By: kkobayas on Wed, 29 June 1994 09:23
		Re: Inverting indices? By: robijn on Wed, 29 June 1994 13:26
		Re: Inverting indices? By: dball on Thu, 07 July 1994 08:57
		Language Documentation; was: Re: Inverting indices? By: caron on Fri, 08 July 1994 08:49

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