| converting ieee-float-format to pw-wave-float-format [message #2667] |
Thu, 25 August 1994 04:40  |
SLAMECZKA
Messages: 4
Registered: August 1994
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Junior Member |
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In <Cv1q43.JJ4@hpl.hp.com> peter@hpl.hp.com writes:
> SLAMECZKA,MICHAEL (SLAMECZKA@EZINFO.VMSMAIL.ETHZ.CH) wrote:
> : I have an 4 byte float in the ieee-format and should convert it into the
> : pw_wave-format.
> There's a difference?
Yes there had to be a difference. Every computer has its own format to save
floats into a byte array and that programm produces an output in the ieee-
format.
> : To do so, I had to shift the byte by 2, that means:
> : byte1 byte2 byte3 byte4 had to be shifted:
> : --> byte3 byte4 byte1 byte2
> : in pw_wave I do the following
> : readu,1,flo
> : print,flo ---> byte3 byte4 byte1 byte2
> : print,float(flo,0) ---> floaatingpointnumber
> Ah, maybe you need to byteswap your data (did you transfer it from one
> CPU type to another?) Try the BYTEORDER command. From your
> description, I think you need BYTEORDER, /LSWAP.
Sorry, BYTEORDER does not produce the right output, I have tried all the
'input keywords'.
> : now my problem realy starts:
> : the result is only one quarter of the original number, that means, if I had
> : a 10 then i get as result in pw_wave 2.5!!!
> Never seen this!
> : thanks a lot
> Hope this helps,
> Peter
your solution Peter does not help,
is anybody out there, who has a better solution?
Thanks in advance
Michael
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