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Re: Arrays with NaN values [message #41253]

Mon, 04 October 2004 16:58

Mark Hadfield
Messages: 783
Registered: May 1995

Senior Member

David Fanning wrote:
>
> I think I would try something like this:
>
> index = Where(Finite(image) EQ 0, count)
> IF count NE 0 THEN image[index] = 0

Note that the first line could *not* be replaced by the (apparently
reasonable)

index = Where(NOT Finite(image), count)

because the NOT operator and the WHERE function do not play well
together. The reasons are explained here:

http://www.dfanning.com/code_tips/bitwiselogical.html

In IDL 6.0 the logical not operator, "~" operator was introduced to
avoid this problem, so the following would work

index = Where(~Finite(image), count)

--
Mark Hadfield "Ka puwaha te tai nei, Hoea tatou"
m.hadfield@niwa.co.nz
National Institute for Water and Atmospheric Research (NIWA)

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[Message index]

		Re: Arrays with NaN values By: Mark Hadfield on Mon, 04 October 2004 16:58
		Re: Arrays with NaN values By: David Fanning on Mon, 04 October 2004 13:35
		Re: Arrays with NaN values By: julio on Mon, 04 October 2004 10:08
		Re: Arrays with NaN values By: David Fanning on Sun, 03 October 2004 22:22
		Re: Arrays with NaN values By: julio on Sun, 03 October 2004 13:36
		Re: Arrays with NaN values By: David Fanning on Sat, 02 October 2004 23:30
		Re: Arrays with NaN values By: Paul Van Delst[1] on Tue, 05 October 2004 09:13

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