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Re: 2 arrays, average, missing data [message #45411]

Thu, 08 September 2005 10:31

James Kuyper
Messages: 425
Registered: March 2000

Senior Member

Benjamin Luethi wrote:
> An short answer would be:
>
> C = (A+B)/((A NE 0)+(B NE 0))
>
> The divisor is 1+1=2 if both A and B are not 0.
> 0+1=1 if one of them is 0.
> 0+0=0 if both A and B are 0.
>
> If A and B are integer, divison by zero produces 0, which is the wanted
> result.
> If A or B are of type double or float, the third case produces NaN.
> Convert it
> to zero using:
>
> sel = where(finite(C,/NaN),count)
> if count gt 0 then C[sel] = 0

Simpler:
C = (A+B)/((A NE 0)+(B NE 0) > 1.0)

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[Message index]

		Re: 2 arrays, average, missing data By: James Kuyper on Thu, 08 September 2005 10:31
		Re: 2 arrays, average, missing data By: kimberlite on Thu, 08 September 2005 08:46
		Re: 2 arrays, average, missing data By: Benjamin Luethi on Thu, 08 September 2005 08:24
		Re: 2 arrays, average, missing data By: Craig Markwardt on Thu, 08 September 2005 07:55
		Re: 2 arrays, average, missing data By: R.G. Stockwell on Thu, 08 September 2005 07:53
		Re: 2 arrays, average, missing data By: David Fanning on Thu, 08 September 2005 07:38

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