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Re: -9999 datas! [message #65591]

Wed, 11 March 2009 23:03

d.poreh
Messages: 406
Registered: October 2007

Senior Member

Thank you very much.
Cheers

On Mar 11, 6:09 pm, ed.schm...@gmail.com wrote:
> Well, you could replace all of your -9999 values with the not-a-
> number !values.f_nan (called NaN), and then selectively replace each
> NaN using mean(w,/nan) in windows whose indices are specified by w.
> (When nan is set in the mean function, any array elements with an NaN
> are skipped.) How big the window must be depends on how closely spaced
> the -9999 values are, and how much averaging you wish to do.
>
> There may be "canned" routines that will do the entire job for you,
> but I don't know of any myself.
>
> Ed Schmahl
>
> d.po...@gmail.com wrote:
>> Folks
>> I have a problem. I have an image with some -9999 data I want to
>> replace these pixels by average of four neighbours. Any help? How come
>> do this if -9999s are in the edges?
>> Cheers

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		Re: -9999 datas! By: d.poreh on Wed, 11 March 2009 23:03
		Re: -9999 datas! By: ed.schmahl on Wed, 11 March 2009 10:09

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