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Re: IDL Way to Remove Rows of an Array [message #75981]

Tue, 10 May 2011 12:37

Gray
Messages: 253
Registered: February 2010

Senior Member

On May 10, 9:48 am, David Fanning <n...@idlcoyote.com> wrote:
> David Fanning writes:
>
> Sorry, but these lines:
>
>> ; The rows must be a vector.
>> IF N_Elements(rows) EQ 1 THEN rows = [rows]
>
> Should be written like this:
>
> ; The rows must be a vector.
> IF Size(rows, /N_DIMENSIONS) EQ 0 THEN rows = [rows]
>
> Cheers,
>
> David
>
> --
> David Fanning, Ph.D.
> Fanning Software Consulting, Inc.
> Coyote's Guide to IDL Programming:http://www.idlcoyote.com/
> Sepore ma de ni thui. ("Perhaps thou speakest truth.")

JD Smith would probably say that it's faster to construct your own
index arrays, right? Maybe like this?

nrow = n_elements(goodrows)
cols = rebin(lindgen(dims[0]),[dims[0],nrow],/sample)
rows = rebin(transpose(goodrows),[dims[0],nrow],/sample)

return, array[cols,rows]

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[Message index]

		Re: IDL Way to Remove Rows of an Array By: Gray on Tue, 10 May 2011 12:37
		Re: IDL Way to Remove Rows of an Array By: David Fanning on Tue, 10 May 2011 06:48
		Re: IDL Way to Remove Rows of an Array By: David Fanning on Tue, 10 May 2011 06:42
		Re: IDL Way to Remove Rows of an Array By: Foldy Lajos on Tue, 10 May 2011 06:01
		Re: IDL Way to Remove Rows of an Array By: JDS on Tue, 17 May 2011 09:59

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