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Re: replacing "NAN" values using interpolation in IDL [message #82782]

Thu, 17 January 2013 07:05

Jeremy Bailin
Messages: 618
Registered: April 2008

Senior Member

On 1/17/13 4:02 AM, idlhelp wrote:
> Dear all, I have an data array. I have many "NaN" values. I want to replace those "NaN" values by the nearby values either using interpolation. Is there any way to do that in IDL.
>
> Thanks in advance
>

Yes, there is.

Oh, you want to know how? ;-)

I would do something like this, if I had an array of locations x and a
data array data:

; sample data
x = [1., 2., 3., 5., 7., 7.5, 9., 12., 12.1]
data = [0., !values.f_nan, 10., 15., !values.f_nan, !values.f_nan, 5.,
4., 5.]

; figure out where there are NaNs and where the useful data are
gooddata = where(data eq data, ngooddata, $
comp=baddata, ncomp=nbaddata)

; interpolate at the locations of the bad data using the good data
if nbaddata gt 0 then begin
data[baddata] = interpol(data[gooddata], x[gooddata], x[baddata])
endif

-Jeremy.

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[Message index]

		Re: replacing "NAN" values using interpolation in IDL By: Jeremy Bailin on Thu, 17 January 2013 07:05
		Re: replacing "NAN" values using interpolation in IDL By: abc on Mon, 28 January 2013 09:27

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