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Re: CMIP5 model output [message #83859]

Thu, 11 April 2013 15:27

DavidF[1]
Messages: 94
Registered: April 2012

Member

siumt...@gmail.com wrote:

> how can you convert CMIP5 model output time to the Julian day?

I don't know how CMIP5 does this, but normally time is expressed as "number of days since 1600-01-01", or something like that. So, to create the correct Julian day number you do this:

time = time + Julday(1,1,1600,0,0,0)

Then, when you want months, days, and years, you convert these Julian values with CatDat:

CatDat, time, month, day, year

Cheers,

David

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		Re: CMIP5 model output By: DavidF[1] on Thu, 11 April 2013 15:27
		Re: CMIP5 model output By: Phillip Bitzer on Thu, 11 April 2013 13:09

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