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Count duplicate elements in an array but keep their order! [message #85750]

Fri, 30 August 2013 16:23

Steve Daal
Messages: 13
Registered: October 2011

Junior Member

Hi,

I have a long array that looks like:
a =[
-120.09796
-120.09796
-108.18972
-108.18972
-108.18972
-121.98
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.23
-95.03
-95.03
-95.03
-95.03
-71.303756
-122.39084
-122.39084
-122.39084
-122.24503]

with many more elements inside. I need to create two new arrays with the consecutive counts corresponding to the values of the first array after removing the duplicates, for instance, the above array would give me:
a_new = [-120.09796, -108.18972, -121.98, -95.23, -71.303756, -122.24503]
and
b_new = [2, 3, 1, 13, 1, 4]

where, elements -120.09796" existed twice in the original array and so forth.
Any help is much appreciated.

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[Message index]

		Count duplicate elements in an array but keep their order! By: Steve Daal on Fri, 30 August 2013 16:23
		Re: Count duplicate elements in an array but keep their order! By: Josh Sixsmith on Sat, 31 August 2013 08:03
		Re: Count duplicate elements in an array but keep their order! By: David Fanning on Tue, 03 September 2013 05:58
		Re: Count duplicate elements in an array but keep their order! By: Steve Daal on Mon, 16 September 2013 10:51

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