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Mean = NaN if NaN present [message #91766]

Mon, 24 August 2015 16:56

laura.hike
Messages: 87
Registered: September 2013

Member

Hi,

I (obviously) using data with NaNs filling in for bad data. I would like to take the mean of a subset of the data and have it fail (return NaN) if any NaNs are included in the subarray. If I use

a = mean(subarray, /NaN)

this only eliminates the NaNs from the computation, meaning that a mean would be returned even if there was only one good value in the subarray. Is there any way to do this besides incorporating an IF statement before the computation, such as

if (total(finite(subarray)) eq n_elements(subarray)) then a = mean(subarray) else a = !Values.F_NAN

which is not only convoluted but may be a nuisance to implement when indices are used to define the subarray?

Thanks,

Larry

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[Message index]

		Mean = NaN if NaN present By: laura.hike on Mon, 24 August 2015 16:56
		Mean = NaN if NaN present By: Helder Marchetto on Tue, 25 August 2015 01:11
		Re: Mean = NaN if NaN present By: Jeremy Bailin on Tue, 25 August 2015 07:08
		Re: Mean = NaN if NaN present By: laura.hike on Tue, 25 August 2015 14:45

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