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NaN doesn't work! [message #93350]

Mon, 20 June 2016 15:11

Libo Wang
Messages: 6
Registered: October 2009

Junior Member

Hi, I have an array with negative numbers (-99.0) representing invalid values. I need to use Total to do some calculation, so I'm converting the invalid values to NaN first:

print,data[60,31,1]
bad=where(data lt 0.0,cbad)
if cbad gt 0 then data[bad]=nan
print,data[60,31,1]

I've got -99.0 from both the print line!! Anybody knows why? I thought I knew how to do some simple IDL coding, now I'm not sure!

Thanks in advance!
Jenny

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[Message index]

		NaN doesn't work! By: Libo Wang on Mon, 20 June 2016 15:11
		Re: NaN doesn't work! By: Dick Jackson on Mon, 20 June 2016 16:41

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