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Convert 8 byte array to double [message #94015]

Wed, 21 December 2016 02:25

LNpellen
Messages: 37
Registered: November 2009

Member

I'm working with DICOM files where a floating number is saved as BYTE array[8] and I know (at least pretty sure) it is a double precision floating number, but I cannot figure out how to convert it to DOUBLE.

IDL> help, a
A BYTE = Array[8]
IDL> print, a
51 51 51 51 51 51 227 63
IDL> print, string(a)
333333ã?
IDL> print, string(a, format='(Z)')
33 33 33 33 33 33 E3 3F
IDL> print, double(a)
51.000000 51.000000 51.000000 51.000000 51.000000 51.000000 227.00000 63.000000

I understand that I can calculate it myself, but that will require a whole lot of code and quite some reading to understand howto. Anybody know of an easier way? As DOUBLE really is a 64bit number...

I have also a feeling that this is swapped endian, or what it is called. (3F first, 33 last).

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[Message index]

		Convert 8 byte array to double By: LNpellen on Wed, 21 December 2016 02:25
		Re: Convert 8 byte array to double By: Heinz Stege on Wed, 21 December 2016 02:47
		Re: Convert 8 byte array to double By: Heinz Stege on Wed, 21 December 2016 03:19

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